**Question 12:-** Jaspal Singh repays his total loan Rs 1,18,000 by paying every month starting with the Ist instalment of Rs 1000, If he increases the instalment by Rs 100 every month, what amount will be paid by him in the 30th instalment ? What amount of loan will he still have to pay after the 30th instalment ? ** [CBSE 2012]**

**Solution:-** Jaspal Singh repays his total loan = Rs 1,18,000

Ist instalment = Rs 1000

IInd instalment = Rs 1100

IIIrd instalment = Rs 1200

Then, the amount forms an A. P. with a constant increasing amount Rs 100. Thus, the series is :

1000, 1100, 1200, 1300 . . .

Now the 30th instalment

⇒

⇒

**Now the 30th instalment = Rs 3900**

Amount paid by Jaspal Singh in 30 instalment

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⇒

⇒

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He paid in 30 instalment = Rs 73,500

**Remaining amount of loan = 1,18,000 – 73,500**

** = Rs 44,500**

### Some other question

**Question 1:** Ramkali would require Rs 5000 for getting her daughter admitted in a school after a year. She saved Rs 150 in the first month and increased her monthly by Rs 50 every month. Find, if she will be able to arrange the required money after 12 months. Which value is reflected in her efforts ?

**Solution: **For solution click here

**Question 2:** The first term of an A.P. is -5 and the last term is 45. If the sum of the terms of the A.P. is 120, then find the number of terms and the common difference.

**Solution:** For solution **Click Here**

**Question 3:** If the sum of the first 6 terms of an A.P. is 36 and that of the first 16 terms is 256, find the sum of the first 10 terms.

**[CBSE 2016, 13, 12]**

**Solution:** For solution** click here**

**Question 4:** The digits of a positive number of three digits are in A.P. and their sum is 15. The number obtained by reversing the digits is 594 less than the original number. Find the number.

**Solution :** For solution **click here**