Jaspal Singh repays his total loan Rs 1,18,000 by paying

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Question 12:- Jaspal Singh repays his total loan Rs 1,18,000 by paying every month starting with the Ist instalment of Rs 1000, If he increases the instalment by Rs 100 every month, what amount will be paid by him in the 30th instalment ? What amount of loan will he still have to pay after the 30th instalment ?      [CBSE   2012]

Solution:- Jaspal Singh repays his total loan = Rs 1,18,000

Ist instalment = Rs 1000

IInd instalment = Rs 1100

IIIrd instalment = Rs 1200

Then, the amount forms an A. P. with a constant increasing amount Rs 100. Thus, the series is :

1000, 1100, 1200, 1300  .   .   .

Now the 30th instalment

a_{30} = a + (30 - 1)d

⇒ a_{30}= 1000 + 29\times 100

⇒a_{30} = 3900

Now the 30th instalment = Rs 3900

Amount paid by Jaspal Singh in 30 instalment

S_{30} = \dfrac{30}{2}[2a + (n - 1)d]

⇒S_{30} = 15[2(1000) + 29(100)]

⇒S_{30} = 15[2000 + 2900]

⇒S_{30} = 15[4900]

⇒S_{30} = 73500

He paid in 30 instalment = Rs 73,500

Remaining amount of loan = 1,18,000 – 73,500

 = Rs 44,500

Some other question

Question 1: Ramkali would require Rs 5000 for getting her daughter admitted in a school after a year. She saved Rs 150 in the first month and increased her monthly by Rs 50 every month. Find, if she will be able to arrange the required money after 12 months. Which value is reflected in her efforts ?

Solution: For solution click here

Question 2: The first term of an A.P. is -5 and the last term is 45. If the sum of  the terms of the A.P. is 120, then find the number of terms and the common difference.

Solution: For solution Click Here

Question 3: If the sum of the first 6 terms of an A.P. is 36 and that of the first 16 terms is 256, find the sum of the first 10 terms.

[CBSE 2016, 13, 12]

Solution: For solution click here

Question 4: The digits of a positive number of three digits are in A.P.  and  their sum is 15. The number obtained by reversing the digits  is 594 less than the original number. Find the number.

Solution : For solution click here

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