Case study problem determinant 1 chapter 4 class 12

Case study Chapter 4 (Determinant)

Case study 1:–  Read the following and answer the questions(Case study problem determinant 1)

           Three friends Rahul, Ravi and Rakesh went to a vegetable market to purchase vegetable. From a vegetable shop Rahul purchased 1 kg of each potato, onion and Brinjal for a total of ₹ 21. Ravi purchased 4 kg of potato, 3 kg of onion and 2 kg of Brijal for ₹ 60 while Rakesh purchased 6 kg potato, 2 kg onion and 3 kg Brinjal for ₹70

(i) If the cost of potato, onion and Brinjal are ₹ x, ₹y and ₹z per kg respectively, then algebraic representation of given situation of problem is

(a) x + y + z = 6, x + y + 3z = 11, 3x + 2y + z = 2

(b) x + y + z = 21, 4x + 3y + 2z = 60, 6x + 2y + 3z = 70

(c) 2x + 3y + z = 21, x + y + z = 60, x + 2y + z = 70

(d) x + y + z = 70, 4x + 2y + 2z = 21, 6x + 2y + 3z =6

(ii) The algebraic representation obtained in question (i) is represented in matrix-system as

(a) AX = B, \text{ where } A = \begin{bmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{bmatrix},X=\begin{bmatrix} x\\ y \\ z\end{bmatrix}, B = \begin{bmatrix} 21\\ 60 \\ 70\end{bmatrix}

(b) AX = B, \text{ where } A = \begin{bmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{bmatrix},X=\begin{bmatrix} 21\\ 60 \\ 70\end{bmatrix}, B = \begin{bmatrix} x\\ y \\ z\end{bmatrix}

(c) A = BX, \text{ where } A = \begin{bmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{bmatrix},X=\begin{bmatrix} x\\ y \\ z\end{bmatrix}, B = \begin{bmatrix} 21\\ 60 \\ 70\end{bmatrix}

(d) AB = X, \text{ where } A = \begin{bmatrix} 1 & 1 & 21 \\ 4 & 3 & 60\\ 6 & 2 & 70\end{bmatrix},X=\begin{bmatrix} x\\ y \\ z\end{bmatrix}, B = \begin{bmatrix} 1\\ 2 \\ 3\end{bmatrix}

(iii) If Ax = B, where A, X, B are matrix then X should be 

(a) X = AB                  (b) X = BA

(c) $X = A^{-1}B$           (d) $X = AB^{-1}$

(iv) If A= \begin{bmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{bmatrix}$ then $A^{-1} is

(a) -\frac{1}{5}\begin{bmatrix} 5 & -1 & -1 \\ 0 & -3 & 2\\ 0 & 4 & 0\end{bmatrix}

(b) -\frac{1}{5} \begin{bmatrix} 5 & -1 & -1 \\ 0 & 3 & 0\\ -10 & 4 & -1\end{bmatrix}

(c) \begin{bmatrix} 5 & -1 & -1 \\ 0 & -3 & 2\\ -10 & 4 & -1\end{bmatrix}

(d) -\frac{1}{5}\begin{bmatrix} 5 & -1 & -1 \\ 0 & -3 & 2\\ -10 & 4 & -1\end{bmatrix}

(v) The cost of potato, onion and Brinjal are

(a) ₹5,₹8 and ₹8             (b) ₹4,₹8 and ₹11

(c) ₹4,₹11 and ₹10          (d) ₹4,₹8 and ₹15

Solution (i) answer(b)

From question

For Rahul x + y + z = 21

For Ravi 4x + 3y + 2z = 60

For Rakesh 6x + 2y + 3z = 70

Therefore algebraic representaion is

x + y + z = 21

4x + 3y + 2z = 60

6x + 2y + 3z = 70

(ii) Answer (a)

The given algebraical system of linear question can be written in matrix system as

AX = B

where, A is coefficient matrix

A = \begin{bmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{bmatrix}

X is variable matrix

X=\begin{bmatrix} x\\ y \\ z\end{bmatrix}

and B is a constant matrix

B = \begin{bmatrix} 21\\ 60 \\ 70\end{bmatrix}

(iii) Answer (c)

We have AX = B

Pre multiplying by A^{-1} on both sides, we have

A^{-1}AX=A^{-1}B

\Rightarrow (A^{-1}A)X=A^{-1}B

\Rightarrow IA = A^{-1}B

\Rightarrow X=A^{-1}B

(iv) Answer (d)

We have

A = \begin{bmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{bmatrix}

|A|= \begin{vmatrix} 1 & 1 & 1 \\ 4 & 3 & 2\\ 6 & 2 & 3\end{vmatrix}

|A| = 1(9-4)-1(12-12)+(8-18)

= 5 - 0 - 10 = -5\neq 0

Now,

A_{11}=(9-4)=5, A_{12}=-(3-2)=-1, A_{13}=(2-3)=-1

A_{21}=-(12-12)=0, A_{22}=(3-6)=-3, A_{23}=-(2-4)=2

A_{31}=(8-18)=-10, A_{32}=-(2-6)=4, A_{33}=(3-4)=-1

\therefore Adj(A) = \begin{bmatrix} 5 & 0 & -10 \\ -1 & -3 & 4\\ -1 & 2 & -1\end{bmatrix}^T

= \begin{bmatrix} 5 & -1 & -1 \\ 0 & -3 & 2\\ -10 & 4 & -1\end{bmatrix}

A^{-1} = \frac{Adj(A)}{|A|}

=-\frac{1}{5}\begin{bmatrix} 5 & -1 & -1 \\ 0 & -3 & 2\\ -10 & 4 & -1\end{bmatrix}

(v) Answer (a)

We have

X = A^{-1}B

\Rightarrow  \begin{bmatrix} x\\ y \\ z\end{bmatrix} = -\frac{1}{5}\begin{bmatrix} 5 & -1 & -1 \\ 0 & -3 & 2\\ -10 & 4 & -1\end{bmatrix}.\begin{bmatrix} 21\\ 60 \\ 70\end{bmatrix}

\Rightarrow  \begin{bmatrix} x\\ y \\ z\end{bmatrix} = -\frac{1}{5}.\begin{bmatrix} -25\\ -40 \\ -40\end{bmatrix}

\Rightarrow  \begin{bmatrix} x\\ y \\ z\end{bmatrix} = \begin{bmatrix} 5\\ 8 \\ 8\end{bmatrix}

Hence x = 5, y = 5, and z = 8

Cost of potato,onion and brinjal are ₹5, ₹8 and ₹8.


Some other Case study problem

Case study 2:- Read the following and answer the question(Case study problem determinant 2)

         Reshma wants to donate a rectangular plot of land for a school of her village. When she was asked by construction agency to give dimensions of the plot, she said that if its length is decreased by 50 m and breadth is increased by 50m, then its area will remain same, but if length is decreased by 10 m and breadth is decreased by 20m, then its area will decreased by 5300 m².

Case study problem determinant 2
Reshma wants to donate a rectangular plot of land for a school of her village.

(i) If length of recangular plot of land be x m and breadth y m then the situation described in problem may be written in system of linear equation as

Solution: For solution click here

Case study 3:– Read the following and answer the question(Case study problem determinant 3 )

              The monthly incomes of two sister Reshma and Ritam are in the ratio 3:4 and their monthly expenditures are in the ratio 5;7. Each sister saves ₹ 15,000 per month.

Case study problem determinant 3
The monthly incomes of two sister Reshma and Ritam are in the ratio 3:4

Solution : For solution click here

Case study 4:– Read the following and answer the question(Case study problem determinant 4)

   On the occasion of children’s day. Class teacher of class XII shri singh, decided to donate some money to students of class XII.

Case study problem determinant 4
On the occasion of children’s day. Class teacher of class XII shri singh,

      If there were 8 studens less, every one would have got ₹10 more, however if there were 16 students more, everyone would have got ₹10 less.

Solution: For solution click here

Case study 5:– In coaching institutes, the students not only get academic guidance but also they get to know about career options and right goals as per their interest and academic record.(Case study problem determinant 5)

Case study problem determinant 5
In coaching institutes, the students not only get academic guidance but also they get to know about career options

A coaching institute conduct classes in two sections A and Band fees for rich and poor children are different. In section A, there are 20 poor and 5 rich children and total monthly collection is ₹9,000, where  as in section B, there are 5 poor and 25 rich children and total monthly collection is ₹ 26, 000.

Solution: For solution click here


 

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