Case study problem matrix 1 chapter 3 class 12

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Case study Chapter 3 (Matrix)

Case study 1:- Read the following and answer the question(Case study problem matrix 1)

   A manufacturer produces three stationery products Pencil, Eraser and Sharpner which he sells in two markets. Annual sales are indicated below

Case study problem matrix 1
A manufacturer produces three stationery products Pencil, Eraser

Market

 Products (in numbers)

Pencil

 Eraser Sharpner

A

 10,000 2,000

18,000
B 6,000 20,000

8,000

If the unit sale price of Pencil, Eraser and Sharpner are ₹ 2.50, ₹ 1.50 and ₹1.00 respectively, and unit cost of the above three commodities are ₹ 2.00, ₹ 1.00 and ₹ 0.50 respectively, then,

(i) Total revenue of market A is

(a) ₹ 64,000              (b) ₹ 60,400

(c) ₹ 46,000               (d) ₹ 40,600

(ii) Total revenue of market B is

(a)  ₹ 35,000              (b) ₹ 53,000

(c) ₹ 50,300               (d) ₹ 30,500

(iii) Cost incurred in market A is

(a) ₹ 13,000                (b) ₹30,100

(c) ₹ 10,300                 (d) ₹ 31,000

(iv) Profit in market A and B respectively are

(a) (₹ 15,000, ₹ 17,000)          (b) (₹ 17,000, ₹ 15000)

(c) (₹ 51,000,  ₹ 71,000)          (d) (₹ 10,000, ₹ 20,000)

(v) Gross profit in both market is

(a) ₹ 23,000              (b) ₹ 20,300

(c) ₹ 32,000               (d) ₹30,200

Solution: (i) Answer (c)

Total revenue for market A

= \begin{bmatrix} 10,000 & 2000 & 18000\end{bmatrix}\begin{bmatrix} 2.50 \\ 1.50 \\1.00\end{bmatrix}

= 10,000×2.50 + 2000×1.50 + 18000×1.00

= ₹46000

(ii) Answer (b)

Total revenue for market B

= \begin{bmatrix} 6,000 & 20,000 & 8000\end{bmatrix}\begin{bmatrix} 2.50 \\ 1.50 \\1.00\end{bmatrix}

= 6,000×2.50 + 20,000×1.50 + 8000×1.00

= ₹ 53000

(iii) Answer (a)

Cost incurred in market A

= \begin{bmatrix} 10,000 & 2000 & 18000\end{bmatrix}\begin{bmatrix} 2.00 \\ 1.00 \\0.50\end{bmatrix}

= 10,000×2.00 + 2000×1.00 + 18000×0.50

= ₹ 31,000

(iv) Answer (a)   

= \begin{bmatrix} 6,000 & 20,000 & 8000\end{bmatrix}\begin{bmatrix} 2.00 \\ 1.00 \\0.50\end{bmatrix}

= 6,000×2.00 + 20,000×1.00 + 8000×0.50

= ₹ 36,000

Profit in market A = ₹ 46000 – ₹ 31000 = ₹ 15000

Profit in market B = ₹ 53000 – ₹ 36000 = ₹ 17000

(v) Answer (c)

Gross profit = Profit in market A + Profit in market B

= ₹ 15000 + ₹ 17000

Case study 2:- Amit, Biraj and chirag were giventhe task of creating a square matrix of order 2. Below are the matrices created by them. A, B, C are the matrices created by Amit, Biraj and Chirag respectively.(Case study problem matrix 2)

Case study problem matrix 2
Amit, Biraj and chirag were giventhe task of creating a square matrix of order 2

Solution: For solution click here

Case study 3:- Read the following and answer the question:(Case study problem matrix 3)

        Three schools DPS, CVC and KVS decided to organize a fair for collecting money for helping the flood victims. They sold Handmade fans, Mats and plates from recycled material at a cost of ₹25, ₹ 100 and ₹50 each respectively. The number of articles sold are given as.

Case study problem matrix 3
Three schools DPS, CVC and KVS decided to organize a fair for collecting money

Solution: For solution click here

 

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