## Chapter 5 Miscellaneous ncert math solution class 11

Chapter – 5(Miscellaneous Exercise) Complex Numbers and Quadratic Equations Chapter 5 Miscellaneous ncert math solution class 11 Question 1: Evaluate: Solution : Given Question 2: For any two complex numbers and , prove that: Solution: Let and Therefore, Now Question 3: Reduce to the standard form. Solution :Given that Question 4: If prove that Solution … Read more

## Exercise 5.3 complex no. ncert math solution class 11

Exercise 5.3(Complex Numbers and Quadratic Equations) Solve each of the following equations:(Exercise 5.3 complex no. ncert math solution class 11) Question 1:  . Solution : The given quadratic equation is . Question 2: . Solution: The given quadratic equation is . On comparing the given equation with , we obtain , and Therefore, the discriminant … Read more

## Exercise 5.2 complex no. ncert math solution class 11

Exercise 5.2 (Complex number) Find the modulus and the arguments of each of the complex numbers in Exercises 1 to 2.(Exercise 5.2 complex no. ncert math solution class 11) Question 1: Solution : Let Comparing the real and imaginary parts, we have Squaring and adding equation (1) and (2), we have Therefore, modulus Now, dividing … Read more

## Exercise 5.1 complex no. ncert math solution class 11

Exercise 5.1(Complex Number) Express each of the complex number given in the Exercises 1 to 10 in the form a + ib.(Exercise 5.1 complex no. ncert math solution class 11) Question 1: Solution: Question 2: Solution: Question 3: Solution: Question 4: Solution: Question 5: Solution: Question 6: Solution: Question 7: Solution: Question 8: Solution: Question … Read more

## Class 12 ncert solution math exercise 5.6

EXERCISE 5.6 If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find.(Class 12 ncert solution math exercise 5.6) Question 1: , Solution: Given, Then, Question 2: Solution: Given, Then, Question 3: Solution: Given, Then, Question 4: Solution: Given, Question 5: Solution: Given, Then, … Read more

## Class 12 ncert solution math exercise 5.3

Exercise 5.3 Find in the following(Class 12 ncert solution math exercise 5.3) Question 1: 2x + 3y = sin x Solution: 2x + 3y = sin x Differentiate with respect to x Question 2:- 2x + 3y = sin y Solution :- 2x + 3y = sin y Differentiate w.r.t. … Read more

## Class 12 ncert solution math exercise 5.2

Exercise 5.2(Continuity and differentiability) Differentiate the functions with respect to x in Exercises 1 to 8.(Class 12 ncert solution math exercise 5.2) Question 1:-  Solution: Differentiate w.r.t. x Question 2:- Solution:- Differentiate w.r.t. x Question 3:- Solution:- Differentiate w.r.t. x Question 4:- Solution:- Differentiate with respect to x Question 5:-  Solution: Differentiate with respect to … Read more

## Class 12 ncert solution math exercise 5.1

Exercise 5.1 (Continuity and Differentiability) Question 1: Prove that the function is continuous at and at . (Class 12 ncert solution math exercise 5.1) Solution: The given function is At Therefore, is continous at . Therefore, is continous at . Therefore, is continous at . Question 2: Examine the continuity of the function at . … Read more

## Class 12 ncert solution math exercise 5.5 differentiation

EXERCISE 5.5 ( Differentiation ) Differentiate the function with respect to (Class 12 ncert solution math exercise 5.5 differentiation) Question 1:   Solution: Let Taking logarithm on both the sides, we obtain Differentiating both sides with respect to , we obtain Question 2:Differentiate the function with respect to Solution: Let Taking logarithm on … Read more

## Class 12 ncert solution math chapter 5 miscellaneous

Chapter 5 Miscellaneous (differentiation ) Differentiate w.r.t. x the function in Exercises 1 to 11.(Class 12 ncert solution math chapter 5 miscellaneous) Question 1: Solution: Let Differentiate with respect to x Question 2: Solution: Let Differentiate with respect to x Question 3: Solution: Let Taking ‘log’ both side Question 4: Solution: Let Differentiate with respect … Read more