In a group activity class, there are 10 students whose

Case study 1:

In a group activity class, there are 10 students whose age are 16, 17, 15, 14, 19, 17, 16, 19, 16 and 15 years. One student is selected at random such that each has equal chance of being chosen and age of the student is recorded.

In a group activity class, there are 10 students whose

On the basis of the above information, answer the following question:

(i) Find the probability that the age of the selected student is a composite number.          1

(ii) Let X be the age of the selected student. What can be the value of X ?                    1

(iii) (a) Find the probability distributionof random variable X and hence find the mean age.      2

                                          OR

(b) A student was selected at random and his age was found to be greater than 15 years. Find the probability that his age is a prime number.                                  2             [CBSE  2023]

Solution:

(i) The age of the selected student is a composite number = 14, 15, 15,16, 16, 16

The probability = 6/10 = 3/5

(ii) the value of X = 14, 15, 16, 17, 19

(iii)(a)The probability distributionof random variable X

The mean age = ΣXP(X)

=  14 × 1/10 + 15 × 2/10 + 16 × 3/10 + 17 × 2/10 + 19 × 2/10

= 14/10 + 30/10 + 48/10 + 54/10 + 38/10

= 174/10 = 17.4

Hence the mean age  = 17.4 

OR

(b) Let the student whose age greater than 15 =  A

Age of the student is prime =  B

The student whose age greater than 15 (A)= {16, 16, 17, 17, 19, 19}

Number of student whose age greater than 15  n(A)= 6

The student whose age are prime (B) = {17, 17, 19, 19}

Now,   A ∩ B = {17, 17, 19, 19}

P( A ∩ B) = 4/10

P(A)  =  6/10

Hence, the probability that his age is a prime number and given that age of the student is greater than 15

P(B/A) = P( A ∩ B)/P(A)

= 4/6  = 2/3

Case study 2:

A housing society wants to commission a swimming pool for its residents. For this, they have to purchase a square piece of land and dig this to such a depth that its capacity is 250 cubic metres. Cost of land is Rs 500 per square metre. The cost of digging increases with the depth and cost for the whole pool is Rs 4000 (depth)²

Suppose the side of the square plot is x metres and depth is h metres. On the basis of the above information, answer the following question:

(i) Write cost C(h) as function in terms of h.

(ii) Find critical point.

(iii) (a) Use second derivative test to find the value of h for which cost of constructing the pool is minimum. What is the minimum cost of construction of the pool ?

                OR

(iii) (b) Use first derivative test to find the depth of the pool so that cost of construction is minimum. Also, find relation between x and h for minimum cost.                         [CBSE   2023]

Solution : For solution click here

Case study 3:

In an agricultural institute, scientists do experiments with varieties of seeds to grow them in different environments to produce healthy plants and get more yield.

A scientist observed that a particular seed grew very fast after germination. He had recorded growth of plant since germinantion and he said that its growth can defined by the function

f(x) = 1/3 x³- 4x² + 15 x + 2, 0≤ x ≤ 10

Where x is the number of days the plant is exposed to sunlight.

On the basis of the above information, answer the following question:

(i) What are the critical points of the function f(x) ?

(ii) Using second derivative test, find the minimum value of the function.            [CBSE  2023]

Solution: For solution click here

 

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